Here is a minimal query that demonstrates the problem. In 9.1 it works:
chris=# select * FROM current_user u join (current_user u cross join current_user v) x on true;
u | u | v
-------+-------+-------
chris | chris | chris
(1 row)
On 9.3 it fails:
ERROR: table name "u" specified more than once
It may be a silly example but it works.
On Wed, Sep 11, 2013 at 5:07 PM, Andreas <maps.on@xxxxxxx> wrote:
I took your sample and modified it a bit.
ERROR: table name "tblb" specified more than once
Switch tblB and tblC in the subquery and it works.select *
WITH
tblA (a_id, a_val) AS ( VALUES (1::integer, 'one-1'::varchar) )
, tblB (b_id, b_val) AS ( VALUES (1::integer, 'one-b'::varchar) )
, tblC (c_id, c_val) AS ( VALUES (1::integer, 'one-c'::varchar) )
from tblA
join tblB on tblA.a_id = tblB.b_id
join (
tblB
join tblC on tblC.c_id = tblB.b_id
) as x on tblA.a_id = x.c_id;
Am 12.09.2013 00:52, schrieb David Johnston:
Andreas-3-2 wrote
I never placed a bug-report. :}Sure.
Could you give a hand?
PostgreSQL homepage (postgresql.org)
"Report a Bug" link on right-hand side of page.
Fill in the form.
SEND THIS>>>>
drop table if exists sub_tab;
drop table if exists main_tab;
drop table if exists flag_1;
drop table if exists flag_2;
create temporary table flag_1 ( flag_1_id integer primary key, flag_1_t
text );
insert into flag_1 values (0, null ), ( 1, 'a' ), ( 2, 'b' ), ( 3, 'c' );
create temporary table flag_2 ( flag_2_id integer primary key, flag_2_t
text );
insert into flag_2 values (0, null ), ( 1, 'a' ), ( 2, 'b' ), ( 3, 'c' );
create temporary table main_tab ( main_id integer primary key, main_t
text, flag_1_id integer references flag_1 ( flag_1_id ) );
insert into main_tab values ( 1, 'Main 1', 1 ), ( 2, 'Main 2', 2 ), ( 3,
'Main 3', 3 );
create temporary table sub_tab ( sub_id integer primary key, sub_t
text, main_id integer references main_tab ( main_id ), flag_1_id integer
references flag_1 ( flag_1_id ), flag_2_id integer references flag_2 (
flag_2_id ) );
insert into sub_tab values ( 1, 'Sub 1', 1, 3, 1 ), ( 2, 'Sub 2', 2, 2,
2 ), ( 3, 'Sub 3', 3, 1, 3 );
select m.main_id, m.main_t, f.flag_1_t,
x.sub_id, x.sub_t, x.flag_1_t, x.flag_2_t
from main_tab as m
join flag_1 as f using ( flag_1_id )
left join
(
sub_tab as s
join flag_2 as f2 using ( flag_2_id ) -- that
way it works
join flag_1 as f using ( flag_1_id )
-- join flag_2 as f2 using ( flag_2_id ) -- that
way it doesn't work
) as x using ( main_id );
--
View this message in context: http://postgresql.1045698.n5.nabble.com/PG-9-3-complains-about-specified-more-than-once-Those-views-worked-in-PG-9-1-9-2-tp5770489p5770534.html
Sent from the PostgreSQL - general mailing list archive at Nabble.com.
--
Sent via pgsql-general mailing list (pgsql-general@xxxxxxxxxxxxxx)
To make changes to your subscription:
http://www.postgresql.org/mailpref/pgsql-general
Best Wishes,
Chris Travers
Efficito: Hosted Accounting and ERP. Robust and Flexible. No vendor lock-in.
