Alexander Reichstadt <info@xxxxxxxxxxxxxx> writes: > I think I solved it: > SELECT * FROM (SELECT DISTINCT ON(refid_messages) refid_messages as msgid, * FROM messagehistorywithcontent WHERE (lower(ARRAY_TO_STRING(ARRAY[login,firstname,lastname,content,msgtitle], ' ')) LIKE '%gg%') ORDER BY refid_messages DESC) as foo ORDER BY messagekind ASC This is not really a solution, unless you don't care which of the rows with a particular refid_messages value comes out. Usually, use of "DISTINCT ON (x)" should be accompanied by "ORDER BY x, y", where y is what you want to determine which row of a given x value comes out. If you write it like this, you get the row with smallest y for each x; or you could write "ORDER BY x, y DESC" to get the row with largest y. See the DISTINCT ON example in the SELECT reference page. regards, tom lane -- Sent via pgsql-general mailing list (pgsql-general@xxxxxxxxxxxxxx) To make changes to your subscription: http://www.postgresql.org/mailpref/pgsql-general
