On 12/08/2011 17:04, George MacKerron wrote: > Hi all. > > I have a function returning setof record. The name of a table it acts > on is one of its input variables, and its output is a set of rows > from that table. E.g. for simplicity, imagine it's this pointless > function: > > create or replace function select_all_from(table_name text) returns > setof record as $$ declare begin return query execute 'select * from > ' || quote_ident(table_name); end $$ language 'plpgsql' stable; > > When I now query this I have to do something like the following, with > an 'as' clause specifying what is going to be returned: > > select column_a from select_all_from('some_table') as (column_a > integer, column_b text); > > When some_table has a lot of columns, this is a real pain. I see in > the PG documentation that each table is also a type of its own. Thus > I had hoped to be able to write the following instead: > > select id from select_all_from('some_table') as some_table; > > However, this is rejected ('a column definition list is required for > functions returning "record"'). > > So -- is there some other syntax or workaround that I can use to can > achieve this -- i.e. to persuade PG to accept a table type in lieu of > a manually-recreated column definition list? What you need to do is declare your function as returning the table type: create or replace function my_function(....) returns my_table as..... And then you can do simply: select * from my_function(....) HTH, Ray. -- Raymond O'Donnell :: Galway :: Ireland rod@xxxxxx -- Sent via pgsql-general mailing list (pgsql-general@xxxxxxxxxxxxxx) To make changes to your subscription: http://www.postgresql.org/mailpref/pgsql-general