(NOTE: I don't use outlook [Mozilla on a Linux box], but I'm gonna top
post and fully quote)
I'm not certain what you want but this might be an alternative to what
you are trying to do (It might not perform better).
SELECT DISTINCT t1.*
FROM log t1, log t2
WHERE t1.date_time BETWEEN $dategt AND $datelt
AND t2.date_time BETWEEN $dategt AND $datelt
AND t1.name = '$username'
AND t2.name = '$username'
AND t1.date_time BETWEEN t2.date_time AND t2.date_time +
t2.session_time
ORDER BY t1.name ASC /* I don't see why you need to do this since you
are looking at one name anyway */, t1.date_time DESC
Tweak as needed for indexes and such.
name='$username' AND \
date_time>$dategt AND date_time<$datelt
Dave [Hawk-Systems] wrote:
looking for a better way to query and cehck for overlapping timeframes.
am selecting records for display that has 3 fields of importance;
date_time (unix timestamp)
session_time (in seconds)
user_id (text field)
Of all the sessions recorded, we are looking for a count of duplicate sessions
for a given month. currently we are doing this with two seperate calls, but it
is taking forever to process;
# first query is to gather sessions that took place within a given month
$query = "SELECT * FROM logs WHERE name='$username' AND \
date_time>$dategt AND date_time<$datelt \
ORDER BY date_time DESC";
$result = pg_exec($database,$query);
$numrows=pg_numrows($result);
for($count=0;$count<$numrows;$count++){
$row = pg_fetch_array($result,$count);
# as we go through the hits, check for duplicates within that timeframe as well
$DUPquery = "SELECT session_id FROM logs WHERE name='$username' AND \
date_time>$sessionstart AND \
(date_time - session_time)<$datetime \
ORDER BY name ASC, date_time DESC";
$DUPresult=pg_exec($database,$DUPquery);
$DUPcount=pg_numrows($DUPresult);
Obviously this is extremely processor intensive, not to mention it seems sloppy.
Any better recommendations, either on altering the above code, or another way to
get the information we require?
Dave
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TIP 8: explain analyze is your friend
