Re: Long Running Update

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24.06.11 14:16, Harry Mantheakis написав(ла):

> EXPLAIN the statement

Here is the EXPLAIN result:

----------------------------------------------------------------------
QUERY PLAN
----------------------------------------------------------------------
Hash Join (cost=2589312.08..16596998.47 rows=74558048 width=63)
Hash Cond: (table_A.id = table_B.id)
-> Seq Scan on table_A(cost=0.00..1941825.05 rows=95612705 width=47)
-> Hash (cost=1220472.48..1220472.48 rows=74558048 width=20)
-> Seq Scan on table_B(cost=0.00..1220472.48 rows=74558048 width=20)
----------------------------------------------------------------------

The documentation says the 'cost' numbers are 'units of disk page fetches'.

Do you, by any chance, have any notion of how many disk page fetches can be processed per second in practice - at least a rough idea?

IOW how do I convert - guesstimate! - these numbers into (plausible) time values?
No chance. This are "virtual values" for planner only.
If I read correctly, your query should go into two phases: build hash map on one table, then update second table using the map. Not that this all valid unless you have any constraints (including foreign checks, both sides) to check on any field of updated table. If you have, you'd better drop them. Anyway, this is two seq. scans. For a long query I am using a tool like ktrace (freebsd) to get system read/write calls backend is doing. Then with catalog tables you can map file names to relations (tables/indexes). Then you can see which stage you are on and how fast is it doing. Note that partially cached tables are awful (in FreeBSD, dunno for linux) for such a query - I suppose this is because instead on sequential read, you get a lot of random reads that fools prefetch logic. "dd if=table_file of=/dev/null bs=8m" helps me a lot. You can see it it helps if CPU time goes up.

Best regards, Vitalii Tymchyshyn

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