Re: Estimation issue with partitioned tables

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Robert,

>> Yeah, I can generate one pretty easily; the behavior is readily
>> observable and repeatable.  Will get on it RSN, but at you said, we're
>> not doing anything about it for 9.0.

Well, I can generate a test case, but on examination it turns out to be
nothing to do with partitioning; it's just good old "n-distinct
underestimation", and not really related to partitioning or joins.

--Josh Berkus

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