Hi Sugumar,
I might misunderstand your need but 'Hex' (as 'Base64') is just an encoding
method to ease use of characters that are not printable.
Your example hex string IV : "12345678901234567890123456789012" should be
converted to :
unsigned char IV[16] = { 0x12, 0x34, 0x56, 0x78, 0x90, 0x12, 0x34, 0x56,
0x78, 0x90, 0x12, 0x34, 0x56, 0x78, 0x90, 0x12 };
in other words = { 18, 52, 86, 120, 144, 18, 52, 86,
120, 144, 18, 52, 86, 120, 144, 18 }; (decimal values)
-----Message d'origine-----
De?: openssl-users [mailto:openssl-users-bounces at openssl.org] De la part de
Sugumar
Envoy??: lundi 22 f?vrier 2016 06:10
??: openssl-users at openssl.org
Objet?: Re: [openssl-users] Problem in decryption using python which cipher
text is encrypted in c++
Thanks for your reply.
Correct me if i am wrong.
What i have understood from your point is, i have to read the first 2 char
of 32 char IV and convert into a byte array right?
For example: my IV "12345678901234567890123456789012"
I have read first 2 char i.e "12" then i have to convert it into byte array.
Please give me some more clear idea about this.
If u have any example for this please post it for our better understanding.
Thanks.
