MH,
If I am not mistaken, then data abort exception is available on arm. Ours is ppc (e6500). Don't think this exception is supported.
"Write a simple function to perform a CPU write through the linear mapping address."
Can you please elaborate on this? How exactly to do this? Pardon my ignorance. I am not much of a kernel programmer.
Thank you for your help so far. Appreciate it.
-Regards
Nikhil
On Fri, Sep 16, 2016 at 4:52 AM, Min-Hua Chen <orca.chen@xxxxxxxxx> wrote:
On Thu, Sep 15, 2016 at 4:23 PM, Nikhil Utane <nikhil.subscribed@xxxxxxxxx> wrote:MH,Let me give a bit of background of the issue.We are facing an issue where 4 bytes of physical memory is getting corrupted (set to 0) at a fixed offset.This offset is always fixed 0x00A4DDC0 (PFN: 0xA4D). The problem manifests in form of SIGILL for some random user-space application where its text area is corrupted. At this moment we are not able to identify who is causing the corruption. While we continue to investigate that (no HW breakpoint support :(), I thought we could at least mask the problem since we know the corruption is always occurring at a fixed offset.Therefore we want to reserve the memory so that kernel does not give it to anyone.We tried passing it via kernel command-line parameter (using memblock) but did not see it working. Finally we modified the function early_reserve_mem_dt() in file "linux-3.12.19/arch/powerpc/kernel/prom.c" to directly reserve the memory. base1 = 0xA4D000; size1=0x1000;memblock_reserve(base1, size1);To check if reservation is working and to monitor the corruption we wrote a kernel module that does a ioremap to page 0xA4D. We then poison it with fixed data. What we found was that, in few runs, this memory was intact and in few others it would change. We tried both memblock_reserve() as well as memblock_remove(). Unfortunately we continue to get the SIGILL at the same offset.Is there any other way to block a physical memory page?ioremap code (relevant lines):static char* sigill_mon_addr;#define ADDR_TEST 0xA4D00sigill_mon_addr = (char*)ioremap(ADDR_TEST, 4096);-ThanksNikhilHi Nikhil,How can a reserved page or reserved page with no-map causes a SIGILL? The reserved page should not beallocated to other users. Your applications should be fine even the corruption remains on the reserved page.I think you have to make sure the page is reserved reserved on your system.For a memblock_remove() pages. Write a simple function to perform a CPU write through the linear mapping address.You should get a data abort and make sure that no CPU can access the page. If the corruption remains, the corruptionmay be caused by other H/W modules.-MHOn Thu, Sep 15, 2016 at 5:35 AM, Min-Hua Chen <orca.chen@xxxxxxxxx> wrote:On Wed, Sep 14, 2016 at 3:17 PM, Nikhil Utane <nikhil.subscribed@xxxxxxxxx> wrote:Thank You MH Chen for your response.So does that mean with memblock_reserve(), a kernel module can call phys_to_virt(), create a linear mapping and modify that memory?Where as with memblock_remove(), a kernel module can call ioremap() and then modify the memory?Not really. It depends on the wether the reserved memory is in a linear mapping range. For example, arm32 only creates linear mappingwithin 1GB range because arm32 has only 1GB of kernel space virtual memory. arm64 creates linear mapping for a large rangeof memory (depends on ARM64_VA_BITS_xx).for memblock_remove() memory, You can use ioremap() to access the memory.What would explain that only in some runs the memory is modified and in some runs it is not (for both the functions)? Shouldn't this reserved/removed memory never be modified unless someone is directly trying to write to that specific page?They should not be modified. How do you write to the reserved memory? Can you post the source code?-MH-RegardsNikhilOn Sun, Sep 11, 2016 at 6:08 AM, Min-Hua Chen <orca.chen@xxxxxxxxx> wrote:Hi Nikhil,memblock_reserve() adds a given memory to the "memblock.reserved" list, it ends up to mark the given range of pages as "reserved". It means the pages are reserved and will not be allocated to other users. The kernel still can see the pages, create linear mappings on them, even access them by linear mappings.memblock_remove() removes a given memory from the "memblock.memory" list, it ends to removed from kernel's memory management system. The memory will not have page structure, no linear mapping on them. It prevents the memory from CPU accessing by the linear address. To access the memory (by CPU), you must use ioremap() to create a mapping to them.MH ChenOn Fri, Sep 9, 2016 at 5:29 PM, Nikhil Utane <nikhil.subscribed@xxxxxxxxx> wrote:______________________________Hi,I want to reserve a physical memory page with a fixed PFN. I do not want this page to be used by anyone else. I am calling memblock_reserve() to supposedly reserve the page. I am writing some content into this page. What I see is that during some runs the content of this page is modified (either fully or sometimes partially). In few runs, I see it as intact. Is it expected that even after calling memblock_reserve() the kernel can allocate this physical page for any other purpose? How is memblock_remove() different from memblock_reserve? I tried reading up but didn't see any useful information. What I understood is memblock_remove will completely remove from kernel's allocation mechanism. Should I then be using remove instead of reserve?-ThanksNikhil_________________
Kernelnewbies mailing list
Kernelnewbies@xxxxxxxxxxxxxxxxg
https://lists.kernelnewbies.org/mailman/listinfo/kernelnewbi es
_______________________________________________ Kernelnewbies mailing list Kernelnewbies@xxxxxxxxxxxxxxxxx https://lists.kernelnewbies.org/mailman/listinfo/kernelnewbies
