Re: Init task 8192 byte alignment query.

[tech learner <techlearn2526@xxxxxxxxx>]

Because L1 cache is 8k deep.

On Wed, Jun 29, 2016 at 10:31 PM, Shiva Shankar <klshiva4a4@xxxxxxxxx> wrote:

Hi 
I was going through arm vmlinux script file. and i found  below statements

/*

* first, the init task union, aligned

* to an 8192 byte boundary.

*/

 INIT_TASK_DATA(THREAD_SIZE)

#define INIT_TASK_DATA(align) \

. = ALIGN(align); \

*(.data..init_task)

As i know we align data structures on a n byte boundary to save access time

and for speed execution but i did not understand why do we need to align this particular data structure on a 8192 byte boundary. 

sometimes it will be on 1024 or 2048 byte boundary.

Any inputs would be appreciated!!!

Regards

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