Hello.
Could anybody help with kexec. I cannot find some informaton from google.
I try to use kexec for fast boot new kernel but I have error below:
# kexec -l /boot/vmlinuz-3.12.0-rc1+ --initrd=/boot/initramfs-3.12.0-rc1+.img --command-line="$(cat /proc/cmdline)"
kexec_load failed: Operation not permitted
entry = 0x24eff5790 flags = 3e0000
nr_segments = 3
segment[0].buf = 0x7fd169783210
segment[0].bufsz = 505250
segment[0].mem = 0x24d000000
segment[0].memsz = 1413000
segment[1].buf = 0xbc3770
segment[1].bufsz = 4310
segment[1].mem = 0x24efef000
segment[1].memsz = 5000
segment[2].buf = 0xbba650
segment[2].bufsz = 90e0
segment[2].mem = 0x24eff5000
segment[2].memsz = b000
KEXEC option in the config is enabled.
How can I decid this problem?
Regards,
Dmitry
_______________________________________________ Kernelnewbies mailing list Kernelnewbies@xxxxxxxxxxxxxxxxx http://lists.kernelnewbies.org/mailman/listinfo/kernelnewbies
