On Thu, 14 Feb 2013 15:33:48 +0200, Kevin Wilson said: > Hi, > > 0x08048000 address is the start address of the code segment of a > program in on x86-32. More likely, it was the start address of *one particular run* of the program. In most kernel configurations, there's something called Address Space Layout Randomization (ASLR) that makes the code land at different places each time, to make it harder to write exploits because you can't hardcode addresses. > What is the start address of the code segment of the program on x86-64 ? > > Is there a place in the kernel code where I can add a printk on a > x86_64 machine to view the code segment > start ? How can it be done ? cat /proc/self/smaps and ponder for a while. Try it twice and compare and see if you can see what ASLR does. You may also want to think about *why* you want to know where the code segment starts. If you know what this address is, what do you plan to use it for? (In other words, there's probably a different, easier way to do whatever it is you're trying to accomplish here)...
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