I think , the problem is there
temp1 = exterint
temp1 is pointer to pointer,not pointer to int but you assigned adress of exterint1 and this array of integer; not array of pointer.
For example like this give you same warning:
int * temp1;
int a;
temp1 = a;
Warrning:“assignment from incompatible pointer type
This is correct if you do like below
int *temp1
int exterint[5];
temp1 = exterint;
Monday, December 24, 2007, 11:49:37 AM, you wrote:
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Dear all: I write a program like below:
#include<stdio.h> #include<stdlib.h> int exterint[5][5]; int exterint1[5]; int main(void){ int index0, index1; int **temp1; int *temp2; temp2=exterint1; //***** temp1 = exterint; //xxxxxxxxx ….. …..}
The compiler will warn me that at line marked as xxxxx is “assignment from incompatible pointer type.” But “******” doesn’t get any warning.
Is there any restriction about assigning multi-layer array or something about pointer I miss?
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