where can I get the standard include path of gcc

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Dear all:
Below are my source code.
#include<stdio.h>
#include<asm-i386/Types.h>

int main(void){
    u64 u64value;

    u64value = 0x2e32;
    printf("u64value = %0x\n",u64value);
}

While compiling it, the gcc tells me that it cannot find the Type.h.
I also  type gcc -v and get message as below
[root@localhost ~]# gcc -v
Using built-in specs.
Target: i386-redhat-linux
Configured with: ../configure --prefix=/usr --mandir=/usr/share/man
--infodir=/usr/share/info --enable-shared --enable-threads=posix
--enable-checking=release --with-system-zlib --enable-__cxa_atexit
--disable-libunwind-exceptions --enable-libgcj-multifile
--enable-languages=c,c++,objc,obj-c++,java,fortran,ada
--enable-java-awt=gtk --disable-dssi
--with-java-home=/usr/lib/jvm/java-1.4.2-gcj-1.4.2.0/jre
--with-cpu=generic --host=i386-redhat-linux
Thread model: posix
gcc version 4.1.1 20060525 (Red Hat 4.1.1-1)

I have read the gcc official document but it seems doesn't mention
where to set or get the standard include path.
Would someone please tell me where can I find the document which will
clarify my concern?

Sincerely Yours,
vichy

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