On Wed, Oct 17, 2007 at 11:39:06AM +0530, chitra wrote: > I am writing some Diagnostics code for a UART chip. > I was able to write most of our test cases from application space using > inb/outb calls. > > To test the 'interrupts' generated by this device, i decided to use the > same application space program to cause interrupts to be generated in the > device and write a simple kernel module which just registers for the static > IRQ line (4 in this case) using the request_irq() call and implements the > ISR . > > On 'insmod', i am able to see the registered module in /proc/interrupts. > The kernel i am using is 2.6.18. > On running the application program, I can see that a interrupt is generated > in the UART.( By checking the respective register) > But, the ISR I have registered is not getting called. I have tried > registering the interrupt with and without sharing, with the same result. > > Am i missing something ? Yes, you forgot to post source code so we can see what you're trying to do. Erik -- They're all fools. Don't worry. Darwin may be slow, but he'll eventually get them. -- Matthew Lammers in alt.sysadmin.recovery
Attachment:
signature.asc
Description: Digital signature
