hello, El Mon, 19 Mar 2007 21:40:53 +0900 "N Cocy" <novu3novrin@xxxxxxxxxxx> ha escrit: > Dear All, > > I saw the following code in linux kernel 2.6's code (arch/sparc/lib/ > atomic32.c #L17). > ( you can also check the code by the following url, > http://www.linux-m32r.org/lxr/http/source/arch/sparc/lib/atomic32.c#L17) > > > spinlock_t __atomic_hash[ATOMIC_HASH_SIZE] = { > > [0 ... (ATOMIC_HASH_SIZE-1)] = SPIN_LOCK_UNLOCKED > > }; > > , where > "SPIN_LOCK_UNLOCKED" returns spinlock_t type of struct, > ATOMIC_HASH_SIZE is defined as "4" just above that function in the > same file, > and "spinlock_t" is defined as struct in include/linux/ > spinlock_types.h file. > > Now, what does the description > > [0 ... (ATOMIC_HASH_SIZE-1)] = SPIN_LOCK_UNLOCKED > > means exactly? > > Does this mean initializing anonymous array or something??? like > [0] = SPIN_LOCK_UNLOCKED > [1] = SPIN_LOCK_UNLOCKED > [2] = SPIN_LOCK_UNLOCKED > [3] = SPIN_LOCK_UNLOCKED > ??? yes > > What I don't understand most is the part "..." in > "[0 ... (ATOMIC_HASH_SIZE-1)]". I've never seen this description in > C before, except for indicating possibility of additional arguments of > a function (but it's still different from the declaration like > "func(arg1, arg2, ...)" ). > this array initialization is a gnu gcc extension, documented at: http://gcc.gnu.org/onlinedocs/gcc/Designated-Inits.html "To initialize a range of elements to the same value, write `[first ... last] = value'." > Could anyone please help me to understand what does this code > mean exactly? > > Thanks in advance. hth, topi > > Cocy > > _________________________________________________________________ > 究極のWEBブラウジング環境を実現！MSN版IE7が待望のデビュー > http://promotion.msn.co.jp/ie7/ > > > -- > To unsubscribe from this list: send an email with > "unsubscribe kernelnewbies" to ecartis@xxxxxxxxxxxx > Please read the FAQ at http://kernelnewbies.org/FAQ > -- To unsubscribe from this list: send an email with "unsubscribe kernelnewbies" to ecartis@xxxxxxxxxxxx Please read the FAQ at http://kernelnewbies.org/FAQ
