Re: RTL8139: TX buffers

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On Wed, Feb 14, 2007 at 10:06:53AM +0900, Roman Mashak wrote:
> Hello, Erik!
> You wrote to "Roman Mashak" <mrv@xxxxxxxxxxxxx> on Tue, 13 Feb 2007 
> 13:13:33 +0100:
> 
> [skip]
> ??>> ...)' call. By the time of this call 'tx_buf' has been properly
> ??>> initialised and contains addresses of 4 TX descriptors. As I
> ??>> understand 'tx_bufs_dma' holds the physical address of DMA memory,
> ??>> while 'tx_bufs' - kernel virtual address. What I can't figure out is
> ??>> the point of  this calculations: tp->tx_bufs_dma + (tp->tx_buf[i] -
> ??>> tp->tx_bufs) Why can't we simply have 'tp->tx_bufs_dma + (i * 4)' ?
> 
> EM> Probably because you can't assume that the buffer addresses are 4 bytes
> EM> apart.
> Why not? Every TX descriptor is of 32 bits length.

Then I don't know. Ask on the netdev mailing list, that's where the
network developers hang out.


Erik

-- 
They're all fools. Don't worry. Darwin may be slow, but he'll
eventually get them. -- Matthew Lammers in alt.sysadmin.recovery

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