Re: which way is faster?

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Ming Zhang wrote:
> On Tue, 2006-12-19 at 18:00 +0200, Momchil Velikov wrote:
>> Ming Zhang wrote:
>>> On Tue, 2006-12-19 at 12:56 +0200, Momchil Velikov wrote:
>>>> Arjan van de Ven wrote:
>>>>> On Mon, 2006-12-18 at 17:12 -0500, Ming Zhang wrote:
>>>>>> See this code piece
>>>>>>
>>>>>> http://lxr.linux.no/source/drivers/scsi/libata-scsi.c?v=2.6.18#L1049
>>>>>>
>>>>>> 1056         lba |= ((u64)scsicmd[2]) << 24;
>>>>>> 1057         lba |= ((u64)scsicmd[3]) << 16;
>>>>>> 1058         lba |= ((u64)scsicmd[4]) << 8;
>>>>>> 1059         lba |= ((u64)scsicmd[5]);
>>>>>>
>>>>>> it can also be written as 
>>>>>>
>>>>>> lba = be32_to_cpu(*(u32 *)(&scsicmd[2])
>>>> ISO/IEC 9899:1999(E) "6.5 Expressions" [#7]
>>> read but still can not understand why u list this here.
>> Because this code
>>
>>    ba = be32_to_cpu(*(u32 *)(&scsicmd[2])
>>
>> violates this requirement
>>
>>   ISO/IEC 9899:1999(E) "6.5 Expressions" [#7]
>>
>> unless you have checked in all callers of ``scsi_10_lba_len'' (and
>> transitively in their callers, if necessary) that the first parameter in
>> fact does refer to an object of type ``u32'', in which case the above
>> code becomes simply non-robust instead of outright non-conforming.
>>
> 
> scsicmd is u8*, so scsicmd + 2 is also u8*, why can not cast it to u32*?
> u* is a unsigned char so a character type" right?

Who said you cannot cast it?  The referred to text in the standard
speaks about *access* to object's stored value, not casts.

~velco

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