A Question about the interrupt 13

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Hello everyone,

I have question about the interrupt 13 and about how the kernel handles
this. I have searched the internet und I have tried to find it in the
kernel sources but unfortunately without any success. I need to know
what the kernel does if I make "int 0x13" which will give me the hd
geometry. I know that I can use ioctl, but in this case I want to know
what the kernel will do when I do "int 0x13". Could someone be so kind
to give me a hint where I can find more information about this issue?

Thanks a lot

Daniel

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