On Wed, 30 Jun 2004, Jan Hudec wrote: > > as i've said b4, i dont see what this macro has to do with the memory > > representation of the null pointer. > > the ((type *)0) member is used to get a pointer to a struct 'type', > > which is located at address 0 -> hence, the address of the member is its > > offset in the struct. nothing to do with actual memory... > > No. ((type *)0) is used to get a NULL pointer of given type. The > C specification DOES say 0 must convert to NULL and does NOT say it must > be located on address 0. In gcc, it always is, though. thats my point. i dont care about C specifications, as u said before, but what gcc does. if ((type *)0) was not located at address 0, this macro would not work. -- ======================================================================== nir. -- Kernelnewbies: Help each other learn about the Linux kernel. Archive: http://mail.nl.linux.org/kernelnewbies/ FAQ: http://kernelnewbies.org/faq/
