Suppose there are two modules, modA and modB. What's going to happen if modB calls a function, modA_func_2(), defined in modA while modA is running another function of its own, modA_func_1()?
I need modA completes modA_func_1() before responsing to modB's call to modA_func_2(). Can I assume kernel will do this for me? If I understand right, a module runs as a single thread process. Therefore, when something is running, other requests must wait. Please correct me if I'm wrong
hi,
The kernel code runs on a behalf of a process. By making kernel modules(and doing insmod), you are attaching your code to the kernel. So your modules also runs ONLY during interrupt handling or system call.
In a Uniprocessor, only one code will be running. Unless using "Preemptive kernel"(available in 2.6) no two process can be running in behalf of kernel. so no question of process A handling modiule 1 and Process B handling module 2.
That is somewhat possible in Solaris. it creates a seperate kernel thread to handle each interrupt and the kernel is preemptive too.
I hope linux kernel developers are working on that and soon be ready.
BTW: Have they started working for 2.7 kernel.
regards manish
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