There comes another newbie question for you guys: I got it while reading the sched.c source file In the function task_rq_lock(), we can see the following code : local_irq_save(*flags); rq = task_rq(p); spin_lock(&rq->lock); What happens if a interruption occurs exactly after local_irq_save() is executed? Wouldn't the state of flags be changed ? I mean, when spin_lock_irqrestore() is executed, won't it restore the wrong flags? (obviouly, in the case that the interrupt occurs) After all, what are this code advantages over some code like: rq = tasq_rq(p); spin_lock_irqsave(&rq->lock); ... spin_lock_irqrestore(&rq->lock); ??? Any answers is welcome :) -- Fortune: It is much easier to be critical than to be correct. -- Benjamin Disraeli --- Software Livre Tecnologia para um mundo melhor ============================== Glauber de Oliveira Costa e-mail: glauber@mpcnet.com.br jabber: glommer@jabber.org ICQ # : 18419549 Phone: +55 19 32892120 ============================== -- Kernelnewbies: Help each other learn about the Linux kernel. Archive: http://mail.nl.linux.org/kernelnewbies/ FAQ: http://kernelnewbies.org/faq/
