Hi, That doesn't answer Seth's question to my mind, and I'm still interested in the answer. If '+''s are the wasted cycles, then if * is an average of the cycles wasted, if there are 'n' competing processes, and k is the avg. utilization for a hyperthreaded CPU, then (trivially) 1 - *^n < k < 1 - *^2n where the max. possible improvement, (*^n - *^2n) should be quite low and insignificant in some cases, and it'd be interesting to know when it's actually significant (or if there's a better measure than avg. cpu utilization). Regards, Sapan > The ``+'' are the wasted cycles, i.e. there *is* a runnable > CPU/process, but it is not scheduled, because the current CPU/process > time quanta is not expired yet. Of course the total time does not > increse with the number of wasted cycles, because there are times when > no CPU/process is runnable. > > ~velco > -- > Kernelnewbies: Help each other learn about the Linux kernel. > Archive: http://mail.nl.linux.org/kernelnewbies/ > FAQ: http://kernelnewbies.org/faq/ > > -- Kernelnewbies: Help each other learn about the Linux kernel. Archive: http://mail.nl.linux.org/kernelnewbies/ FAQ: http://kernelnewbies.org/faq/
