> -----Original Message----- > From: Nick Taylor [mailto:nickt@xxxxxxxxxxxxx] > Sent: Tuesday, September 27, 2005 6:30 PM > To: Derick Anderson > Cc: Alaios; netfilter@xxxxxxxxxxxxxxxxxxx > Subject: RE: Plz i need help.... or i ll be fired :( > > <-------removed on topic discussion to rant off topic------> > > > Your internet address is 143.233.222.77 and your network mask is > > 255.255.255.192. That 192 means you only have 64 IPs in > your network. > > If you don't believe me then google CIDR masks for yourself > like I did > > a couple years back. Now supposing that your network address is > > 143.233.222.76 (and it is probably 143.233.222.64), you run > out of IPs > > at 143.233.222.139, which is your network's default > broadcast address. > > This is quite far away from 143.233.222.253 so your packet > never gets > > to the intended host. > > > > So many people can't understand binary, and it's statements > like the one above that make this so confusing for people. > There's no such thing as a "network address" that doesn't > fall on a subnet boundry. The math is so simple, please try > to understand, it will make the world a better place: Apologies for not being more precise in my post. I was 99% sure of what you just said but figured an in-depth discussion of CIDR masks was overkill - having said that you've provided a more complete and understandable explanation than I probably would have.
