What makes you think you are being attacked? There is not enough information here to make that determination. "408" is a "request Time-out error" and does not mean you are being attacked. This appears to be an ACK scan with spoofed IP addresses. Look at the IPID's and TTL values. They tell me they are coming from the same machine. If you want to drop these packets, create stateful rules for inbound connections to port 80, and they will be dropped: $IPT -t filter -A PORTSCAN_RULES --destination-port 80 -p tcp --tcp-flags ALL ACK -m state --state NEW -j LOG --log-level $LOG_LEVEL --log-prefix "PORTSCAN: ACK ON NEW: " $IPT -t filter -A PORTSCAN_RULES --destination-port 80 -p tcp --tcp-flags ALL ACK -m state --state NEW -j REJECT --reject-with icmp-host-unreachable -----Original Message----- From: netfilter-admin@xxxxxxxxxxxxxxxxxxx [mailto:netfilter-admin@xxxxxxxxxxxxxxxxxxx] On Behalf Of ccddtt Sent: Monday, January 26, 2004 1:00 AM To: netfilter@xxxxxxxxxxxxxxxxxxx Subject: Apache:access_log - 408 hi,all please help me. my linux server installed redhat 9 + apache 1.3.29. passing through some attack. in apache acc_log,like : 221.233.227.230 - - [17/Jan/2004:17:26:32 +0800] "-" 408 - 221.233.227.230 - - [17/Jan/2004:17:26:32 +0800] "-" 408 - 221.233.227.230 - - [17/Jan/2004:17:26:32 +0800] "-" 408 - 61.145.188.110 - - [17/Jan/2004:17:26:32 +0800] "-" 408 - 210.38.179.145 - - [17/Jan/2004:17:26:32 +0800] "-" 408 - 221.233.227.230 - - [17/Jan/2004:17:26:32 +0800] "-" 408 - but no err_log. some packge like : Jan 18 19:35:53 linux-sv1 kernel: IN=eth0 OUT= MAC=00:07:e9:6c:4c:49:00:02:b3:03:e3:67:08:00 SRC=220.173.8.56 DST=61.135.xx.xx LEN=40 TOS=0x00 PREC=0x00 TTL=114 ID=42497 DF PROTO=TCP SPT=60177 DPT=80 WINDOW=8280 RES=0x00 ACK URGP=0 Jan 18 19:35:53 linux-sv1 kernel: IN=eth0 OUT= MAC=00:07:e9:6c:4c:49:00:02:b3:03:e3:67:08:00 SRC=220.173.8.56 DST=61.135.xx.xx LEN=40 TOS=0x00 PREC=0x00 TTL=114 ID=42753 DF PROTO=TCP SPT=60177 DPT=80 WINDOW=8280 RES=0x00 ACK URGP=0 Jan 18 19:35:53 linux-sv1 kernel: IN=eth0 OUT= MAC=00:07:e9:6c:4c:49:00:02:b3:03:e3:67:08:00 SRC=61.173.25.88 DST=61.135.xx.xx LEN=40 TOS=0x00 PREC=0x00 TTL=115 ID=53402 DF PROTO=TCP SPT=63601 DPT=80 WINDOW=16560 RES=0x00 ACK URGP=0 Jan 18 19:35:53 linux-sv1 kernel: IN=eth0 OUT= MAC=00:07:e9:6c:4c:49:00:02:b3:03:e3:67:08:00 SRC=220.173.8.56 DST=61.135.xx.xx LEN=40 TOS=0x00 PREC=0x00 TTL=114 ID=43265 DF PROTO=TCP SPT=60182 DPT=80 WINDOW=8280 RES=0x00 ACK URGP=0 how to set this iptables rules? what's this attack? thanks your any help!
