Pablo Neira Ayuso <pablo@xxxxxxxxxxxxx> wrote:
> On Sun, Apr 01, 2018 at 12:47:47AM +0200, Florian Westphal wrote:
> > this makes following failing test case work:
> > ip6 dscp vmap { 0x04, ..
> >
> > problem was that the 6bit dscp value spans a byte boundary,
> > so payload postprocessing increases the size to a 2 byte access
> > (plus a binop mask operation to discard the unwanted bits).
> >
> > But because set key size was already set based on the previous
> > payload size, we get a set with a keysize of 1 that is then
> > populated with keys of size 2 (which causes a kernel error).
> >
> > So, fixup the set size so kernel is told to expect 2-byte keys
> > in this case.
> >
> > Signed-off-by: Florian Westphal <fw@xxxxxxxxx>
> > ---
> > diff --git a/src/evaluate.c b/src/evaluate.c
> > index d224f0f3c2c1..a1193f7d8456 100644
> > --- a/src/evaluate.c
> > +++ b/src/evaluate.c
> > @@ -1279,6 +1279,8 @@ static int expr_evaluate_map(struct eval_ctx *ctx, struct expr **expr)
> > if (expr_evaluate(ctx, &map->mappings->set->init) < 0)
> > return -1;
> > expr_set_context(&ctx->ectx, ctx->set->key->dtype, ctx->set->key->len);
> > + if (ctx->set->key->len < map->left->len)
> > + ctx->set->key->len = map->left->len;
>
> Will this work with concatenations?
No, concat is still broken, binop_transfer() doesn't handle them.
I'll look into it.
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