On Tue, Apr 06, 2010 at 01:29:50PM -0700, David Daney wrote: > The ebase is relative to CKSEG0 not CAC_BASE. On a 32-bit kernel they > are the same thing, for a 64-bit kernel they are not. > > It happens to kind of work on a 64-bit kernel as they both reference > the same physical memory. However since the CPU uses the CKSEG0 base, > determining if a J instruction will reach always gives the wrong > result unless we use the same number the CPU uses. Applied, thanks! Ralf
