On Mon, 29 Jan 2007 17:27:04 +0100, "Franck Bui-Huu" <vagabon.xyz@xxxxxxxxx> wrote: > It may be interesting to have a look to the assembly code in this case > to see what the compiler does exactly. I compiled ip27 kernel and really confused... head.S: PTR_LA t0, __bss_start # clear .bss LONG_S zero, (t0) System.map: a8000000003b6000 A __bss_start vmlinux: a800000000385058: 3c0c003b lui t0,0x3b a80000000038505c: 658c6000 daddiu t0,t0,24576 a800000000385060: fd800000 sd zero,0(t0) vmlinux.32: 80385058: 3c0c003b lui t4,0x3b 8038505c: 658c6000 daddiu t4,t4,24576 80385060: fd800000 sd zero,0(t4) How does this code work? Isn't address 0x3b6000 in user space? --- Atsushi Nemoto
