Re: why gcc 2.95.3 generate different result with option -mips2 and -mips3 for the same code

[Thiemo Seufer <ica2_ts@xxxxxxxxxxxxxxxxxxxxxxxx>]

glame wrote:
> hi,
> when i disassemble the code, the result is as the following
> 
> -ffffffff80010b8c:  01001021    move    $v0,$t0  (-mips2)
> +ffffffff80010b8c:  0100102d    move    $v0,$t0  (-mips3)
> 
> why? 

Because you told it to do so. :-)
The 32bit move is "addu v0, $0, t0", the 64bit move "daddu ...".


Thiemo