Thank you. For some reason i have been reading ANDI ans ADDI. But i
am still confused at lines 13, 14 and 15
13 imax $8, $6, 0
14 srl $10, $8, 3
15 beq $10, $0, .L62
Thanks for correcting me
Sri
On Thu, 8 Jul 2004 10:59:58 +0200 (MEST), Geert Uytterhoeven
<geert@xxxxxxxxxxxxxx> wrote:
> On Thu, 8 Jul 2004, Sridhar Adagada wrote:
> > As you can see $6 is the length, my confusion is at the lines 12-14,
> > 19, 20 why is the length added with 65535 and the comparison with 0
>
> It's not `added with 65535', but `ANDed with 65535'. MIPS32 has 32-bit integer
> operations only. If you want to do 16-bit math, all data has to be masked.
>
> Anyway, for performance, it's better to do 32-bit math only.
>
> > short cal_xxx(short *abs, short *coef, short len, short base)
> > {
> > short i;
> > short sum = 0;
> >
> > for (i = 0; i < length; i++)
> > {
> > sum += ( (unsigned int)abs[i] * (unsigned int)coef[i] );
>
> Why cast to unsigned int while sum is a short? Unless you really want to rely
> on sum being a short, you better make it int and do the truncation to short
> after the loop.
>
> Gr{oetje,eeting}s,
>
> Geert
>
> --
> Geert Uytterhoeven -- There's lots of Linux beyond ia32 -- geert@xxxxxxxxxxxxxx
>
> In personal conversations with technical people, I call myself a hacker. But
> when I'm talking to journalists I just say "programmer" or something like that.
> -- Linus Torvalds
>
