Michael Buesch wrote:
> On Sunday 15 February 2009 18:05:52 Larry Finger wrote:
>> Roel Kluin wrote:
>>> - | (rfatt->with_padmix) ? txctl_value : 0);
>>> + | (rfatt->with_padmix ? txctl_value : 0));
>> As I see it, the difference between the above two lines is the same as the
>> difference between c and d in this program:
>>
>> int main(int argc, char **argv)
>> {
>> int a = 1, b = 2, c, d;
>>
>> c = (a) ? b : 0;
>> d = (a ? b : 0);
>> fprintf (stderr, "a, b, c, d: %d %d %d %d\n", a, b, c, d);
>> return 1;
>> }
>>
>> When this program is executed, the output line is
>>
>> a, b, c, d: 1 2 2 2
>>
>> which is what I expected. Thus "(condition) ? result1 : result2" is the same as
>> "(condition ? result1 : result2)".
>
> The problem is the binary OR operator, which has precedence over the ?: operator.
I see. Please ignore my noise.
Larry
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