On Sunday 15 February 2009 18:05:52 Larry Finger wrote:
> Roel Kluin wrote:
> > - | (rfatt->with_padmix) ? txctl_value : 0);
> > + | (rfatt->with_padmix ? txctl_value : 0));
>
> As I see it, the difference between the above two lines is the same as the
> difference between c and d in this program:
>
> int main(int argc, char **argv)
> {
> int a = 1, b = 2, c, d;
>
> c = (a) ? b : 0;
> d = (a ? b : 0);
> fprintf (stderr, "a, b, c, d: %d %d %d %d\n", a, b, c, d);
> return 1;
> }
>
> When this program is executed, the output line is
>
> a, b, c, d: 1 2 2 2
>
> which is what I expected. Thus "(condition) ? result1 : result2" is the same as
> "(condition ? result1 : result2)".
The problem is the binary OR operator, which has precedence over the ?: operator.
--
Greetings, Michael.
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