Re: [PATCH 1/2] watchdog: Add support for Armada 37xx CPU watchdog

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Hi Guenter,

One cannot restart the counter to start counting down from initial
value without disabling the counter, but the counter can be made to
restart counting from the initial value by an event which can be set,
and for Counter ID 1 the event can be set to "end count of Counter ID
0".

I have therefore reimplemented the driver so that two counters are
used. Counter ID 1 is used as the watchdog counter, while Counter ID 0
is used to reset Counter ID 1 to start counting from initial value.
Pinging is then done by forcing immediate end count event on Counter ID
0.

I discovered that counters 2 and 3 are enabled by default even before
U-Boot loads on the board, and therefore, in combination with the
previous, decided not to add th possibility to select watchdog counter
as a devicetree property.

What do you think of this?

Marek

On Fri, 31 Aug 2018 17:47:38 -0700
Guenter Roeck <linux@xxxxxxxxxxxx> wrote:

> On 08/31/2018 05:29 PM, Marek Behun wrote:
> > Hello Guenter,
> > I just read in the specification that software does not need to
> > do debouncing, because when low is read, high is latched into 32 bit
> > flip flop so that it can be read correctly.
> > So the correct way is to read low first, then high, and that's it.
> > I shall write a comment describing this into new code.  
> 
> Excellent. Thanks for checking!
> 
> Guenter
> 
> > Marek
> > 
> > On Thu, 30 Aug 2018 12:12:26 -0700
> > Guenter Roeck <linux@xxxxxxxxxxxx> wrote:
> >   
> >> On Thu, Aug 30, 2018 at 08:50:04PM +0200, Marek Behun wrote:  
> >>>>>> +static u64 get_counter_value(struct armada_37xx_watchdog
> >>>>>> *dev) +{
> >>>>>> +	u64 val;
> >>>>>> +
> >>>>>> +	val = readl(dev->reg + CNTR_COUNT_HIGH);
> >>>>>> +	val = (val << 32) | readl(dev->reg +
> >>>>>> CNTR_COUNT_LOW);  
> >>>>>
> >>>>> Is this guaranteed to be consistent ? What happens if there is a
> >>>>> 32-bit wrap between those two operations ?  
> >>>>
> >>>> hmmm. The address is not divisible by 8, so I can't use
> >>>> readq :( what do you propose?  
> >>>
> >>> What do you think of this solution?
> >>>
> >>> u64 val;
> >>> u32 low1, low2;
> >>>
> >>> low1 = readl(dev->reg + CNTR_COUNT_LOW);
> >>> val = readl(dev->reg + CNTR_COUNT_HIGH);
> >>> low2 = readl(dev->reg + CNTR_COUNT_LOW);
> >>>
> >>> /*
> >>>   * If low jumped in this short time more than 2^31, a wrap
> >>> probably
> >>>   * occured. Read high again.
> >>>   */
> >>> if (low2 - low1 > 0x80000000)
> >>> 	val = readl(dev->reg + CNTR_COUNT_HIGH);
> >>> val = (val << 32) | low2;  
> >>
> >> Yes, that is one option. The other would be to read high again
> >> all the time and repeat reading low if high changed on the second
> >> read of high.
> >>
> >> 	high1 = readl(dev->reg + CNTR_COUNT_HIGH);
> >> 	low = readl(dev->reg + CNTR_COUNT_LOW);
> >> 	high2 = readl(dev->reg + CNTR_COUNT_HIGH);
> >> 	if (high2 != high1)
> >> 		low = readl(dev->reg + CNTR_COUNT_LOW);
> >> 	val = (high2 << 32) | low;
> >>
> >> There is no ambiguity in this case: We _know_ that
> >> a wrap occurred if high1 and high2 are different.
> >>
> >> Guenter  
> > 
> >   
> 




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