Re: preop expression and variable

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On Fri, Mar 21, 2014 at 4:02 AM, Guillaume Oberlé <goberle@xxxxxx> wrote:
>
> If you look at the output (l117 or l133), I have a PreopExpression before every variable in an expression statement, even if I have no preoperator.

You need to look at what the op is too, not just the type.

I assume you're talking about EXPR_PREOP-'*'. That's a dereference
("lvalue access").  And yes, it's required. A symbol on its own is
just the address or the symbol. Actually *accessing* that symbol is
that PREOP-*.

            Lnus
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