On 29. 04. 24, 11:14, David Laight wrote:
From: Jiri Slaby
Sent: 29 April 2024 07:39
...
- u8 prescaler = 0;
+ int prescaler = 1;
Ugh, why do you move to signed arithmetics?
Any arithmetic would always have been signed.
u8 is promoted to 'signed int' before being used for pretty much anything.
Sorry, what?
C99 §6.3.8.1 states:
If both operands have the same type, then no further conversion is needed.
Otherwise, if both operands have signed integer types or both have
unsigned integer types, the operand with the type of lesser integer
conversion rank is converted to the type of the operand with greater rank.
=====
I.e. u8 is converted according to that to ulong in this case. So
unsigned arithmetic happens.
'unsigned int prescaler' might have changed arithmetic to be unsigned.
The same as u8.
OTOH you probably don't want a u8 - that might require the compiler
mask an arithmetic result to 8 bits.
Pardon? Not at all.
Am I missing something?
thanks,
--
js
suse labs
