Le 22/08/2016 à 10:42, Arnd Bergmann a écrit :
[...]
Sorry, but I'm not following the logic here.
[...]
You argue that the two have the same meaning, which I see, but
why is it better than the existing code?
Arnd
Hi,
sorry if my explanation was unclear.
What I mean is that if "sizeof(unsigned long) = 4" (i.e. 32 bits systems
?) then:
port = find_first_zero_bit(&vt8500_ports_in_use, sizeof(vt8500_ports_in_use));
turns into:
port = find_first_zero_bit(&vt8500_ports_in_use, 4);
find_first_zero_bit "Returns the bit number of the first set bit. If no bits are set, returns @size."
So, in this case, it can return 1, 2, 3 or 4, if one of the 4 first bits is 0.
And will also return 4, if none of the 4 first bits is 0.
In no way, 5 or above can be returned.
The code just after is:
if (port >= VT8500_MAX_PORTS)
return -ENODEV;
It turns into:
if (port >= 6)
return -ENODEV;
I see 2 problems there:
- First, according to this test, "port = 5" seems a legal value, but can never trigger.
- Second, if the first 3 bits are set, the find_first_zero_bit will return 4, whatever the value of the 4th bit.
This 4 can either mean "4th bit is clear" or "no clear bit found, so return @size (i.e. 4)"
Using:
port = find_first_zero_bit(&vt8500_ports_in_use, BITS_PER_LONG);
Would solve the 2 issues.
- 4 would really mean, 4th bit is set.
- 5 becomes a possible value.
- 6 to 31 would mean: we found a clear bit "in the garbage after the VT8500_MAX_PORTS (i.e. 6) relevant bits".
- 32 would mean, all bits set.
These answers look more in line with the "if (port >= VT8500_MAX_PORTS)" test.
Finally, what I meant by "Other options are possible:" is:
- 'vt8500_ports_in_use' being a 'unsigned long', use ffz to reduce code verbosity
port = ffz(&vt8500_ports_in_use);
would also work, because it is equivalent to:
port = find_first_zero_bit(&vt8500_ports_in_use, BITS_PER_LONG);
- VT8500_MAX_PORTS, in order to be consistent with the test below
port = find_first_zero_bit(&vt8500_ports_in_use, VT8500_MAX_PORTS);
would also work and is maybe more logical in regard to the test "if (port >= VT8500_MAX_PORTS)"
Now if "sizeof(unsigned long) = 8" (i.e. 64 bits systems ?), the actual code would work.
But using "sizeof(long)" to mean "more than VT8500_MAX_PORTS" is odd.
In other words, expressing a number of bits using something that gives a size in bytes is, IMHO, spurious.
All this is pure speculation.
Hoping that it is clearer now ( and that my analysis is right :) )
Best regard,
CJ
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