My applogies: > It may be worth noting (if you're going to update any documentation) that > isn't 100% accurate. You actually get one wrap in partition 1 and the rest > minus one wrap into partition 0. There is one wrap used as a guard between > the two partitions. The size given to a partition is rounded up to the size of a > wrap as well. > > See > https://docs.oracle.com/cd/E21419_04/en/LTO5_Vol3_E5b/LTO5_Vol3_E5b. > pdf > > Page 100 where it gives examples of how partition sizes are calculated on HP > LTO5 drives. I should have actually said: You do get two wraps as a minimum in partition 1 and the rest minus two wraps into partition 0. The extra two wraps are used as a guard between the two partitions and all sizes will be rounded to a multiple of two wraps. That was just to make it clear that partition sizes will always end up being a multiple of 2x the wrap size and that there was some fixed overhead in partitioning an LTO5+ drive (2 wraps). ��.n��������+%������w��{.n�����{������ܨ}���Ơz�j:+v�����w����ޙ��&�)ߡ�a����z�ޗ���ݢj��w�f
