On 10/20/07, Phillip Susi <psusi@xxxxxxxxxx> wrote: > Huang, Ying wrote: > > The hibernation procedure with the patch set is as follow: > > > > 1. Boot a kernel A > > > > 2. Work under kernel A > > > > 3. Kexec another kernel B (crash dump enabled) in kernel A. > > > > 4. Save the memory image of kernel A through crash dump (such as "cp > > /proc/vmcore ~"). Save the "jump back entry". > > Doesn't this also save the memory of kernel B? The memory area of kernel B is excluded from the elf header of /proc/vmcore. This is done in kexec-tools (/sbin/kexec) patches. > > 5. Shutdown or reboot > > > > > > The restore process with the patch set is as follow: > > > > 1. Boot a kernel C (crash dump enabled), the memory area used by > > kernel C must be a subset of memory area used by kernel B. > > Why is a third kernel needed? Why can't kernel B be used for this as > well? In fact, if kernel A has been compiled to be relocatable and > crash dump enabled, why wouldn't it suffice for all 3 instances? One kernel can be used for three situation. In fact, I use just one kernel for testing. Best Regards, Huang Ying _______________________________________________ linux-pm mailing list linux-pm@xxxxxxxxxxxxxxxxxxxxxxxxxx https://lists.linux-foundation.org/mailman/listinfo/linux-pm
