Huang, Ying wrote:
The hibernation procedure with the patch set is as follow: 1. Boot a kernel A 2. Work under kernel A 3. Kexec another kernel B (crash dump enabled) in kernel A. 4. Save the memory image of kernel A through crash dump (such as "cp /proc/vmcore ~"). Save the "jump back entry".
Doesn't this also save the memory of kernel B?
5. Shutdown or reboot The restore process with the patch set is as follow: 1. Boot a kernel C (crash dump enabled), the memory area used by kernel C must be a subset of memory area used by kernel B.
Why is a third kernel needed? Why can't kernel B be used for this as well? In fact, if kernel A has been compiled to be relocatable and crash dump enabled, why wouldn't it suffice for all 3 instances?
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