Re: [PATCH v2] PCI: free of node in pci_scan_device's error path

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On Mon, Jan 25, 2021 at 02:28:26AM +0300, Dmitry Baryshkov wrote:
> In the pci_scan_device() if pci_setup_device() fails for any reason, the
> code will not release device's of_node by calling pci_release_of_node().
> Fix that by calling the release function.
> 
> Fixes: 98d9f30c820d ("pci/of: Match PCI devices to OF nodes dynamically")
> Signed-off-by: Dmitry Baryshkov <dmitry.baryshkov@xxxxxxxxxx>

Applied with Leon's reviewed-by to pci/enumeration for v5.13, thanks!

> ---
> 
> Changes since v1:
>  - Changed the order of Fixes and S-o-B tags.
> 
> ---
>  drivers/pci/probe.c | 1 +
>  1 file changed, 1 insertion(+)
> 
> 
> diff --git a/drivers/pci/probe.c b/drivers/pci/probe.c
> index 953f15abc850..be51670572fa 100644
> --- a/drivers/pci/probe.c
> +++ b/drivers/pci/probe.c
> @@ -2353,6 +2353,7 @@ static struct pci_dev *pci_scan_device(struct pci_bus *bus, int devfn)
>  	pci_set_of_node(dev);
>  
>  	if (pci_setup_device(dev)) {
> +		pci_release_of_node(dev);
>  		pci_bus_put(dev->bus);
>  		kfree(dev);
>  		return NULL;
> -- 
> 2.29.2
> 



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