place_entity() update se->vruntime question

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Hi all,

when a process was wakeup by try_to_wake_up(),it will call
activate_task()to move a task into the run queue,and the parameter
"wakeup=1".

enqueue_task_fair() will call enqueue_entity() to place the schedule
entity to the proper cfs_rq.it will at last call place_entity() with
parameter "initial=0".

As my understanding,the waken up schedule entity has smaller vruntime
than the cfs_rq->min_runtime.But the debug information show that's
random.

So i would like to ask some kind guy,when did " se->vruntime >
cfs_rq->min_vruntime "?

I guess the new waken up process may migrate to another cfs_rq,and its
vruntime bigger than that cfs_rq.

Also if CONFIG_FAIR_GROUP_SCHED=y,the enqueue_task_fair() maybe
traverse se and its parents ,then parameter "wakeup = 1".Then the
parent schedule entity may has larger vruntime than its cfs_rq,it
stands for a group.

Could any one give some suggestion?

Thanks in advance.
--wxc200
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