place_entity() update se->vruntime question

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Hi all,

when a process was wakeup by try_to_wake_up(),it will call activate_task()to move a task into the run queue,and the parameter "wakeup=1".

enqueue_task_fair() will call enqueue_entity() to place the schedule entity to the proper cfs_rq.it will at last call place_entity() with parameter "initial=0".

As my understanding,the waken up schedule entity has smaller vruntime than the cfs_rq->min_runtime.But the debug information show that's random.

So i would like to ask some kind guy,when did " se->vruntime > cfs_rq->min_vruntime "?

I guess the new waken up process may migrate to another cfs_rq,and its vruntime bigger than that cfs_rq.

Also if CONFIG_FAIR_GROUP_SCHED=y,the enqueue_task_fair() maybe traverse se and its parents ,then parameter "wakeup = 1".Then the parent schedule entity may has larger vruntime than its cfs_rq,it stands for a group.

Could any one give some suggestion?

Thanks in advance.
--wxc200
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