Hi Geert > If count is even, we never get that far, so the even numbers should not > be present in your table above? > > If count is odd, "(count - 1) >> 1 == count >> 1". Ahh, yes, indeed. About endianness / byte access, it requires byte access especially "read" case. Because if count was odd number, using shift with u16 will might be buffer overflow I need to check cpu_to_le16() / le16_to_cpu() Best regards --- Kuninori Morimoto -- To unsubscribe from this list: send the line "unsubscribe linux-mmc" in the body of a message to majordomo@xxxxxxxxxxxxxxx More majordomo info at http://vger.kernel.org/majordomo-info.html
