We have: > UDP hash table entries: 128 (order: 0, 4096 bytes) > CONFIG_BASE_SMALL=0 udp_table_init looks like: if (!CONFIG_BASE_SMALL) table->hash = alloc_large_system_hash(name, .. &table->mask); /* * Make sure hash table has the minimum size */ Since CONFIG_BASE_SMALL is 0, we are allocating the hash using alloc_large_system Then: if (CONFIG_BASE_SMALL || table->mask < UDP_HTABLE_SIZE_MIN - 1) { table->hash = kmalloc(); table->mask is 127, and UDP_HTABLE_SIZE_MIN is 256, so we are allocating again table->hash without freeing already allocated memory. We could free table->hash, before allocating the memory with kmalloc. I don't fully understand the condition table->mask < UDP_HTABLE_SIZE_MIN - 1. Eric? thanks, Daniel. -- To unsubscribe, send a message with 'unsubscribe linux-mm' in the body to majordomo@xxxxxxxxxx For more info on Linux MM, see: http://www.linux-mm.org/ . Fight unfair telecom internet charges in Canada: sign http://stopthemeter.ca/ Don't email: <a href=mailto:"dont@xxxxxxxxx"> email@xxxxxxxxx </a>