On Tue, 2020-11-03 at 16:56 +0200, Sakari Ailus wrote:
> On Tue, Nov 03, 2020 at 04:47:47PM +0200, Andy Shevchenko wrote:
> > On Tue, Nov 03, 2020 at 03:34:00PM +0200, Sakari Ailus wrote:
> > > Add a printk modifier %p4cc (for pixel format) for printing V4L2 and DRM
> > > pixel formats denoted by fourccs. The fourcc encoding is the same for both
> > > so the same implementation can be used.
> >
> > ...
> >
> > > +static noinline_for_stack
> > > +char *fourcc_string(char *buf, char *end, const u32 *fourcc,
> > > + struct printf_spec spec, const char *fmt)
> > > +{
> > > + char output[sizeof("(xx)(xx)(xx)(xx) little-endian (0x01234567)")];
> >
> > I would add a comment that there is another possibility, i.e. big-endian, but
> > it occupies less space.
I think it's unnecessary as it's obvious and similarly done in other
<foo>_string type functions.
> > > + p = special_hex_number(p, output + sizeof(output) - 2, *fourcc,
> > > + sizeof(u32));
> >
> > I would go with one line here.
>
> It's wrapped since the result would be over 80 otherwise.
Perhaps simpler as
p = special_hex_number(p, p + 10, *fourcc, sizeof(u32));
> > The (theoretical) problem is here that the case when buffer size is not enough
> > to print a value will be like '(0xabc)' but should be rather '(0xabcd' like
> > snprintf() does in general.
Isn't the stack buffer known to be large enough?
> > > + *p++ = ')';
> > > + *p = '\0';
> > > +
> > > + return string(buf, end, output, spec);
Isn't the actual output buffer used here truncating output?
If the general problem is someone using a limited length pointer
output like %10p4cc, then all the output is getting truncated no?
