On 4/23/24 7:25 PM, Xu Kuohai wrote:
On 4/24/2024 5:55 AM, Yonghong Song wrote:
On 4/20/24 1:33 AM, Xu Kuohai wrote:
On 4/20/2024 7:00 AM, Eduard Zingerman wrote:
On Thu, 2024-04-11 at 20:27 +0800, Xu Kuohai wrote:
From: Xu Kuohai <xukuohai@xxxxxxxxxx>
With lsm return value check, the no-alu32 version
test_libbpf_get_fd_by_id_opts
is rejected by the verifier, and the log says:
0: R1=ctx() R10=fp0
; int BPF_PROG(check_access, struct bpf_map *map, fmode_t
fmode) @ test_libbpf_get_fd_by_id_opts.c:27
0: (b7) r0 = 0 ; R0_w=0
1: (79) r2 = *(u64 *)(r1 +0)
func 'bpf_lsm_bpf_map' arg0 has btf_id 916 type STRUCT 'bpf_map'
2: R1=ctx() R2_w=trusted_ptr_bpf_map()
; if (map != (struct bpf_map *)&data_input) @
test_libbpf_get_fd_by_id_opts.c:29
2: (18) r3 = 0xffff9742c0951a00 ;
R3_w=map_ptr(map=data_input,ks=4,vs=4)
4: (5d) if r2 != r3 goto pc+4 ;
R2_w=trusted_ptr_bpf_map() R3_w=map_ptr(map=data_input,ks=4,vs=4)
; int BPF_PROG(check_access, struct bpf_map *map, fmode_t
fmode) @ test_libbpf_get_fd_by_id_opts.c:27
5: (79) r0 = *(u64 *)(r1 +8) ; R0_w=scalar() R1=ctx()
; if (fmode & FMODE_WRITE) @ test_libbpf_get_fd_by_id_opts.c:32
6: (67) r0 <<= 62 ;
R0_w=scalar(smax=0x4000000000000000,umax=0xc000000000000000,smin32=0,smax32=umax32=0,var_off=(0x0;
0xc000000000000000))
7: (c7) r0 s>>= 63 ;
R0_w=scalar(smin=smin32=-1,smax=smax32=0)
; @ test_libbpf_get_fd_by_id_opts.c:0
8: (57) r0 &= -13 ;
R0_w=scalar(smax=0x7ffffffffffffff3,umax=0xfffffffffffffff3,smax32=0x7ffffff3,umax32=0xfffffff3,var_off=(0x0;
0xfffffffffffffff3))
; int BPF_PROG(check_access, struct bpf_map *map, fmode_t
fmode) @ test_libbpf_get_fd_by_id_opts.c:27
9: (95) exit
And here is the C code of the prog.
SEC("lsm/bpf_map")
int BPF_PROG(check_access, struct bpf_map *map, fmode_t fmode)
{
if (map != (struct bpf_map *)&data_input)
return 0;
if (fmode & FMODE_WRITE)
return -EACCES;
return 0;
}
It is clear that the prog can only return either 0 or -EACCESS,
and both
values are legal.
So why is it rejected by the verifier?
The verifier log shows that the second if and return value setting
statements in the prog is optimized to bitwise operations "r0 s>>=
63"
and "r0 &= -13". The verifier correctly deduces that the the value of
r0 is in the range [-1, 0] after verifing instruction "r0 s>>= 63".
But when the verifier proceeds to verify instruction "r0 &= -13", it
fails to deduce the correct value range of r0.
7: (c7) r0 s>>= 63 ;
R0_w=scalar(smin=smin32=-1,smax=smax32=0)
8: (57) r0 &= -13 ;
R0_w=scalar(smax=0x7ffffffffffffff3,umax=0xfffffffffffffff3,smax32=0x7ffffff3,umax32=0xfffffff3,var_off=(0x0;
0xfffffffffffffff3))
So why the verifier fails to deduce the result of 'r0 &= -13'?
The verifier uses tnum to track values, and the two ranges "[-1,
0]" and
"[0, -1ULL]" are encoded to the same tnum. When verifing instruction
"r0 &= -13", the verifier erroneously deduces the result from
"[0, -1ULL] AND -13", which is out of the expected return range
[-4095, 0].
To fix it, this patch simply adds a special SCALAR32 case for the
verifier. That is, when the source operand of the AND instruction is
a constant and the destination operand changes from negative to
non-negative and falls in range [-256, 256], deduce the result range
by enumerating all possible AND results.
Signed-off-by: Xu Kuohai <xukuohai@xxxxxxxxxx>
---
Hello,
Sorry for the delay, I had to think about this issue a bit.
I found the clang transformation that generates the pattern this patch
tries to handle.
It is located in DAGCombiner::SimplifySelectCC() method (see [1]).
The transformation happens as a part of DAG to DAG rewrites
(LLVM uses several internal representations:
- generic optimizer uses LLVM IR, most of the work is done
using this representation;
- before instruction selection IR is converted to Selection DAG,
some optimizations are applied at this stage,
all such optimizations are a set of pattern replacements;
- Selection DAG is converted to machine code, some optimizations
are applied at the machine code level).
Full pattern is described as follows:
// fold (select_cc seteq (and x, y), 0, 0, A) -> (and (sra (shl
x)) A)
// where y is has a single bit set.
// A plaintext description would be, we can turn the SELECT_CC
into an AND
// when the condition can be materialized as an all-ones
register. Any
// single bit-test can be materialized as an all-ones register with
// shift-left and shift-right-arith.
For this particular test case the DAG is converted as follows:
.---------------- lhs The meaning of
this select_cc is:
| .------- rhs `lhs == rhs ?
true value : false value`
| | .----- true value
| | | .-- false value
v v v v
(select_cc seteq (and X 2) 0 0 -13)
^
-> '---------------.
(and (sra (sll X 62) 63) |
-13) |
|
Before pattern is applied, it checks that second 'and' operand has
only one bit set, (which is true for '2').
The pattern itself generates logical shift left / arithmetic shift
right pair, that ensures that result is either all ones (-1) or all
zeros (0). Hence, applying 'and' to shifts result and false value
generates a correct result.
Thanks for your detailed and invaluable explanation!
Thanks Eduard for detailed explanation. It looks like we could
resolve this issue without adding too much complexity to verifier.
Also, this code pattern above seems generic enough to be worthwhile
with verifier change.
Kuohai, please added detailed explanation (as described by Eduard)
in the commit message.
Sure, already added, the commit message and the change now is like this:
---
bpf: Fix a false rejection caused by AND operation
With lsm return value check, the no-alu32 version
test_libbpf_get_fd_by_id_opts
is rejected by the verifier, and the log says:
0: R1=ctx() R10=fp0
; int BPF_PROG(check_access, struct bpf_map *map, fmode_t fmode) @
test_libbpf_get_fd_by_id_opts.c:27
0: (b7) r0 = 0 ; R0_w=0
1: (79) r2 = *(u64 *)(r1 +0)
func 'bpf_lsm_bpf_map' arg0 has btf_id 916 type STRUCT 'bpf_map'
2: R1=ctx() R2_w=trusted_ptr_bpf_map()
; if (map != (struct bpf_map *)&data_input) @
test_libbpf_get_fd_by_id_opts.c:29
2: (18) r3 = 0xffff9742c0951a00 ;
R3_w=map_ptr(map=data_input,ks=4,vs=4)
4: (5d) if r2 != r3 goto pc+4 ; R2_w=trusted_ptr_bpf_map()
R3_w=map_ptr(map=data_input,ks=4,vs=4)
; int BPF_PROG(check_access, struct bpf_map *map, fmode_t fmode) @
test_libbpf_get_fd_by_id_opts.c:27
5: (79) r0 = *(u64 *)(r1 +8) ; R0_w=scalar() R1=ctx()
; if (fmode & FMODE_WRITE) @ test_libbpf_get_fd_by_id_opts.c:32
6: (67) r0 <<= 62 ;
R0_w=scalar(smax=0x4000000000000000,umax=0xc000000000000000,smin32=0,smax32=umax32=0,var_off=(0x0;
0xc000000000000000))
7: (c7) r0 s>>= 63 ;
R0_w=scalar(smin=smin32=-1,smax=smax32=0)
; @ test_libbpf_get_fd_by_id_opts.c:0
8: (57) r0 &= -13 ;
R0_w=scalar(smax=0x7ffffffffffffff3,umax=0xfffffffffffffff3,smax32=0x7ffffff3,umax32=0xfffffff3,var_off=(0x0;
0xfffffffffffffff3))
; int BPF_PROG(check_access, struct bpf_map *map, fmode_t fmode) @
test_libbpf_get_fd_by_id_opts.c:27
9: (95) exit
And here is the C code of the prog.
SEC("lsm/bpf_map")
int BPF_PROG(check_access, struct bpf_map *map, fmode_t fmode)
{
if (map != (struct bpf_map *)&data_input)
return 0;
if (fmode & FMODE_WRITE)
return -EACCES;
return 0;
}
It is clear that the prog can only return either 0 or -EACCESS,
and both
values are legal.
So why is it rejected by the verifier?
The verifier log shows that the second if and return value setting
statements in the prog is optimized to bitwise operations "r0 s>>=
63"
and "r0 &= -13". The verifier correctly deduces that the the value of
r0 is in the range [-1, 0] after verifing instruction "r0 s>>= 63".
But when the verifier proceeds to verify instruction "r0 &= -13", it
fails to deduce the correct value range of r0.
7: (c7) r0 s>>= 63 ;
R0_w=scalar(smin=smin32=-1,smax=smax32=0)
8: (57) r0 &= -13 ;
R0_w=scalar(smax=0x7ffffffffffffff3,umax=0xfffffffffffffff3,smax32=0x7ffffff3,umax32=0xfffffff3,var_off=(0x0;
0xfffffffffffffff3))
So why the verifier fails to deduce the result of 'r0 &= -13'?
The verifier uses tnum to track values, and the two ranges "[-1,
0]" and
"[0, -1ULL]" are encoded to the same tnum. When verifing instruction
"r0 &= -13", the verifier erroneously deduces the result from
"[0, -1ULL] AND -13", which is out of the expected return range
[-4095, 0].
As explained by Eduard in [0], the clang transformation that
generates this
pattern is located in DAGCombiner::SimplifySelectCC() method (see
[1]).
The transformation happens as a part of DAG to DAG rewrites
(LLVM uses several internal representations:
- generic optimizer uses LLVM IR, most of the work is done
using this representation;
- before instruction selection IR is converted to Selection DAG,
some optimizations are applied at this stage,
all such optimizations are a set of pattern replacements;
- Selection DAG is converted to machine code, some optimizations
are applied at the machine code level).
Full pattern is described as follows:
// fold (select_cc seteq (and x, y), 0, 0, A) -> (and (sra (shl
x)) A)
// where y is has a single bit set.
// A plaintext description would be, we can turn the SELECT_CC
into an AND
// when the condition can be materialized as an all-ones
register. Any
// single bit-test can be materialized as an all-ones register with
// shift-left and shift-right-arith.
For this particular test case the DAG is converted as follows:
.---------------- lhs The meaning of
this select_cc is:
| .------- rhs `lhs == rhs ?
true value : false value`
| | .----- true value
| | | .-- false value
v v v v
(select_cc seteq (and X 2) 0 0 -13)
^
-> '---------------.
(and (sra (sll X 62) 63) |
-13) |
|
Before pattern is applied, it checks that second 'and' operand has
only one bit set, (which is true for '2').
The pattern itself generates logical shift left / arithmetic shift
right pair, that ensures that result is either all ones (-1) or all
zeros (0). Hence, applying 'and' to shifts result and false value
generates a correct result.
As suggested by Eduard, this patch makes a special case for source
or destination register of '&=' operation being in range [-1, 0].
Meaning that one of the '&=' operands is either:
- all ones, in which case the counterpart is the result of the
operation;
- all zeros, in which case zero is the result of the operation.
And MIN and MAX values could be derived based on above two
observations.
[0]
https://lore.kernel.org/bpf/e62e2971301ca7f2e9eb74fc500c520285cad8f5.camel@xxxxxxxxx/
[1]
https://github.com/llvm/llvm-project/blob/4523a267829c807f3fc8fab8e5e9613985a51565/llvm/lib/CodeGen/SelectionDAG/DAGCombiner.cpp
Suggested-by: Eduard Zingerman <eddyz87@xxxxxxxxx>
Signed-off-by: Xu Kuohai <xukuohai@xxxxxxxxxx>
diff --git a/kernel/bpf/verifier.c b/kernel/bpf/verifier.c
index 640747b53745..30c551d39329 100644
--- a/kernel/bpf/verifier.c
+++ b/kernel/bpf/verifier.c
@@ -13374,6 +13374,24 @@ static void scalar32_min_max_and(struct
bpf_reg_state *dst_reg,
dst_reg->u32_min_value = var32_off.value;
dst_reg->u32_max_value = min(dst_reg->u32_max_value, umax_val);
+ /* Special case: src_reg is known and dst_reg is in range [-1,
0] */
+ if (src_known &&
+ dst_reg->s32_min_value == -1 && dst_reg->s32_max_value
== 0 &&
+ dst_reg->smin_value == -1 && dst_reg->smax_value == 0) {
do we need to check dst_reg->smin_value/smax_value here? They should not impact
final dst_reg->s32_{min,max}_value computation, right?
Similarly, for later 64bit min/max and, 32bit value does not really matter.
+ dst_reg->s32_min_value = min_t(s32, src_reg->s32_min_value, 0);
+ dst_reg->s32_max_value = max_t(s32,
src_reg->s32_min_value, 0);
+ return;
+ }
+
+ /* Special case: dst_reg is known and src_reg is in range [-1,
0] */
+ if (dst_known &&
+ src_reg->s32_min_value == -1 && src_reg->s32_max_value
== 0 &&
+ src_reg->smin_value == -1 && src_reg->smax_value == 0) {
+ dst_reg->s32_min_value = min_t(s32,
dst_reg->s32_min_value, 0);
+ dst_reg->s32_max_value = max_t(s32,
dst_reg->s32_min_value, 0);
+ return;
+ }
+
/* Safe to set s32 bounds by casting u32 result into s32 when u32
* doesn't cross sign boundary. Otherwise set s32 bounds to
unbounded.
*/
@@ -13404,6 +13422,24 @@ static void scalar_min_max_and(struct
bpf_reg_state *dst_reg,
dst_reg->umin_value = dst_reg->var_off.value;
dst_reg->umax_value = min(dst_reg->umax_value, umax_val);
+ /* Special case: src_reg is known and dst_reg is in range [-1,
0] */
+ if (src_known &&
+ dst_reg->smin_value == -1 && dst_reg->smax_value == 0 &&
+ dst_reg->s32_min_value == -1 && dst_reg->s32_max_value
== 0) {
+ dst_reg->smin_value = min_t(s64, src_reg->smin_value, 0);
+ dst_reg->smax_value = max_t(s64, src_reg->smin_value, 0);
+ return;
+ }
+
+ /* Special case: dst_reg is known and src_reg is in range [-1,
0] */
+ if (dst_known &&
+ src_reg->smin_value == -1 && src_reg->smax_value == 0 &&
+ src_reg->s32_min_value == -1 && src_reg->s32_max_value
== 0) {
+ dst_reg->smin_value = min_t(s64, dst_reg->smin_value, 0);
+ dst_reg->smax_value = max_t(s64, dst_reg->smin_value, 0);
+ return;
+ }
+
/* Safe to set s64 bounds by casting u64 result into s64 when u64
* doesn't cross sign boundary. Otherwise set s64 bounds to
unbounded.
*/
In my opinion the approach taken by this patch is sub-optimal:
- 512 iterations is too much;
- this does not cover all code that could be generated by the above
mentioned LLVM transformation
(e.g. second 'and' operand could be 1 << 16).
Instead, I suggest to make a special case for source or dst register
of '&=' operation being in range [-1,0].
Meaning that one of the '&=' operands is either:
- all ones, in which case the counterpart is the result of the
operation;
- all zeros, in which case zero is the result of the operation;
- derive MIN and MAX values based on above two observations.
Totally agree, I'll cook a new patch as you suggested.
[1]
https://github.com/llvm/llvm-project/blob/4523a267829c807f3fc8fab8e5e9613985a51565/llvm/lib/CodeGen/SelectionDAG/DAGCombiner.cpp#L5391
Best regards,
Eduard
