Think about a for loop: for (i = 0; i < xxx; i++) { If "i" is really so high that it goes negative you have a very serious issue whether it's signed or unsigned. If it's signed then the loop is a no-op but if it's unsigned then it corrupts memory. That's not a win. regards, dan carpenter -- To unsubscribe from this list: send the line "unsubscribe kernel-janitors" in the body of a message to majordomo@xxxxxxxxxxxxxxx More majordomo info at http://vger.kernel.org/majordomo-info.html