This patch will remove old kernels from system selective way. Signed-off-by: Bhaskar Chowdhury <unixbhaskar@xxxxxxxxx> --- scripts/prune-kernel | 16 ++++++++-------- 1 file changed, 8 insertions(+), 8 deletions(-) diff --git a/scripts/prune-kernel b/scripts/prune-kernel index 74143f229f84..28fae6c91218 100755 --- a/scripts/prune-kernel +++ b/scripts/prune-kernel @@ -33,7 +33,7 @@ printf "\t\n Enlist the installed kernels \n\n\n" cd $boot_dir && pwd #Bash experts not recomend to run ls inside script,but you can by running that too -# ls -1 vmlinuz-* +# ls -1 vmlinuz-* #This is the recommended way , little complex but that's what people want to see! @@ -42,10 +42,10 @@ find $boot_dir -name "vmlinuz-*" -type f -print0 -exec ls -1 {} \; printf "\n\n\n Well, we need to purge some kernel to gain some space.\n\n\n" -printf "Please give the kernel version to remove: %s" +printf "Please give the kernel version to remove: %s" read kernel_version -remove_old_kernel +remove_old_kernel printf "\n\n Remove associated modules too ... \n\n" @@ -54,7 +54,7 @@ cd $modules_dir && pwd printf "\n\n\n Enlist the installed modules \n\n\n" #This is (-1) minus one not l(el) -# ls -1 +# ls -1 find $modules_dir -name "$kernel_version-*" -type f -print0 -exec ls -1 {} \; @@ -66,14 +66,14 @@ rm -rf $modules_version printf "\n\n Done \n\n" printf "\n\n Want to remove another?[Yn] : %s" -read response +read response if [[ $response == "Y" ]]; then - printf "Please give another version to remove : %s" + printf "Please give another version to remove : %s" read kernel_version -remove_old_kernel +remove_old_kernel elif [[ $response == "n" ]]; then @@ -81,4 +81,4 @@ elif [[ $response == "n" ]]; then fi -exit 0 +exit 0 -- 2.21.0