On Wed, Oct 17, 2018 at 08:17:20PM +0530, Nishad Kamdar wrote:
+ chip->rdwr_pin = devm_gpiod_get(&spi_dev->dev, "rdwr", GPIOD_IN); + if (IS_ERR(chip->rdwr_pin)) { + ret = PTR_ERR(chip->rdwr_pin); + dev_err(&spi_dev->dev, "Failed to request rdwr GPIO: %d\n", + ret); return ret; } - gpio_direction_input(chip->rdwr_pin); - ret = devm_gpio_request(&spi_dev->dev, chip->convert_pin, - spi_get_device_id(spi_dev)->name); - if (ret) { - dev_err(&spi_dev->dev, "Fail to request convert gpio PIN %d.\n", - chip->convert_pin); + chip->convert_pin = devm_gpiod_get(&spi_dev->dev, "convert", GPIOD_IN); + if (IS_ERR(chip->convert_pin)) { + ret = PTR_ERR(chip->convert_pin); + dev_err(&spi_dev->dev, "Failed to request convert GPIO: %d\n", + ret); return ret; } - gpio_direction_input(chip->convert_pin); - ret = devm_gpio_request(&spi_dev->dev, chip->busy_pin, - spi_get_device_id(spi_dev)->name); - if (ret) { - dev_err(&spi_dev->dev, "Fail to request busy gpio PIN %d.\n", - chip->busy_pin); + chip->busy_pin = devm_gpiod_get(&spi_dev->dev, "busy", GPIOD_IN); + if (IS_ERR(chip->busy_pin)) { + ret = PTR_ERR(chip->busy_pin); + dev_err(&spi_dev->dev, "Failed to request busy GPIO: %d\n", + ret); return ret; }
Hm, from what I can tell devm_gpio_request() is allocating some memory, which makes this a series of 4 allocations. What happens if the fourth allocation fails? Do we leak the first three? -- Thanks, Sasha