In case of FLUSH operation, BAM copies INPUT EOT FLUSH (0x94) instead of normal EOT (0x93) tag in input data stream when an input EOT tag is received during flush operation. So only one tag will be written instead of 2 separate tags. Signed-off-by: Abhishek Sahu <absahu@xxxxxxxxxxxxxx> Reviewed-by: Andy Gross <andy.gross@xxxxxxxxxx> --- * Changes from v1: None drivers/i2c/busses/i2c-qup.c | 4 ++-- 1 file changed, 2 insertions(+), 2 deletions(-) diff --git a/drivers/i2c/busses/i2c-qup.c b/drivers/i2c/busses/i2c-qup.c index b2e8f57..73a2880 100644 --- a/drivers/i2c/busses/i2c-qup.c +++ b/drivers/i2c/busses/i2c-qup.c @@ -774,10 +774,10 @@ static int qup_i2c_bam_do_xfer(struct qup_i2c_dev *qup, struct i2c_msg *msg, qup->btx.tag.start[0] = QUP_BAM_INPUT_EOT; len++; - /* scratch buf to read the BAM EOT and FLUSH tags */ + /* scratch buf to read the BAM EOT FLUSH tags */ ret = qup_sg_set_buf(&qup->brx.sg[rx_cnt++], &qup->brx.tag.start[0], - 2, qup, DMA_FROM_DEVICE); + 1, qup, DMA_FROM_DEVICE); if (ret) return ret; } -- QUALCOMM INDIA, on behalf of Qualcomm Innovation Center, Inc. is a member of Code Aurora Forum, hosted by The Linux Foundation
