Each iteration of for_each_child_of_node puts the previous node, but in the case of a return from the middle of the loop, there is no put, thus causing a memory leak. Hence add an of_node_put before the return. Issue found with Coccinelle. Signed-off-by: Nishka Dasgupta <nishkadg.linux@xxxxxxxxx> --- drivers/pinctrl/meson/pinctrl-meson.c | 1 + 1 file changed, 1 insertion(+) diff --git a/drivers/pinctrl/meson/pinctrl-meson.c b/drivers/pinctrl/meson/pinctrl-meson.c index 596786926209..8bba9d053d9f 100644 --- a/drivers/pinctrl/meson/pinctrl-meson.c +++ b/drivers/pinctrl/meson/pinctrl-meson.c @@ -651,6 +651,7 @@ static int meson_pinctrl_parse_dt(struct meson_pinctrl *pc, continue; if (gpio_np) { dev_err(pc->dev, "multiple gpio nodes\n"); + of_node_put(np); return -EINVAL; } gpio_np = np; -- 2.19.1